Respuesta

D)

Resolviendo obtenemos:

${\displaystyle \frac{32}{b-6}}+{\displaystyle \frac{40}{b-8}}={\displaystyle \frac{32}{-2-6}}+{\displaystyle \frac{40}{-2-8}}={\displaystyle \frac{32}{-8}}+{\displaystyle \frac{40}{-10}}=-4+-4=-8$